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If x=∣123231312∣x = \begin{vmatrix}1 & 2 & 3 \\ 2 & 3 & 1 \\ 3 & 1 & 2\end{vmatrix} then value of 9−2x9-2x is :

Solution

✅ Correct Option: 3

Expanding: x=1(6−1)−2(4−3)+3(2−9)=5−2−21=−18x = 1(6-1) - 2(4-3) + 3(2-9) = 5 - 2 - 21 = -18. So 9−2x=9−2(−18)=9+36=459-2x = 9-2(-18) = 9+36 = 45.

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