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The area of the triangle with vertices (1,4),(2,7)(1,4), (2,7) and (4,13)(4,13) is :

Solution

✅ Correct Option: 1

Area =12∣1(7−13)+2(13−4)+4(4−7)∣=12∣−6+18−12∣=0= \frac{1}{2} \left| 1(7-13) + 2(13-4) + 4(4-7) \right| = \frac{1}{2} | -6 + 18 - 12 | = 0. The points are collinear.

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