CUET Mathematics - The shortest distance between the lines r = (t+2j+3k)+(2t+3j+4k) and r = (2i+4j+5k)+(3i+4j+5k) is equal to | PYQs + Solutions

CUET Mathematics 2025 13 May Shift 2

Geometry

Hard

core

$\frac{1}{\sqrt{2}}$

$\frac{1}{\sqrt{3}}$

$\frac{1}{2}$

$\frac{1}{\sqrt{6}}$

✅ Correct Option: 4

Related questions:

27 May Shift 1

Match List-I with List-II

Choose the correct answer from the options given below:

30 May Shift 1

Consider the line $\vec{r} = -2\hat{i} + 3\hat{j} + \hat{k} + \lambda(5\hat{i} - 3\hat{j} - \hat{k})$ . Match List-I with List-II

List-I	List-II
(A) A point on the given line	(I) $\left(\frac{5}{\sqrt{35}}, \frac{-3}{\sqrt{35}}, \frac{-1}{\sqrt{35}}\right)$
(B) Direction ratios of the given line	(II) (2, 3, 1)
(C) Direction cosines of the given line	(III) (5, -3, -1)
(D) Direction ratios of a line perpendicular to given line	(IV) (-2, 3, 1)

Choose the correct answer from the options given below:

CUET Mathematics 2024 Slot 1

If the lengths of the three sides of a trapezium other than the base are $10 \mathrm{~cm}$ each, then the maximum area of the trapezium is:

CUET Mathematics 2025 13 May Shift 2 PYQs