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Which of the following statements is (are) true?

(A) BTABB^T AB is a skew-symmetric matrix if A is a symmetric matrix

(B) BTABB^T AB is a symmetric matrix if A is a symmetric matrix

(C) BTABB^T AB is a symmetric matrix if A is a skew-symmetric matrix

(D) BTABB^T AB is a skew-symmetric matrix if B is a skew-symmetric matrix

(E) BTABB^T AB is a symmetric matrix if B is a symmetric matrix

Choose the correct answer from the options given below:

Solution

✅ Correct Option: 3

A matrix is symmetric if MT=MM^T = M and skew-symmetric if MT=−MM^T = -M.

When taking transpose of a product: (AB)T=BTAT(AB)^T = B^T A^T


Testing Statement (A): BTABB^T AB is skew-symmetric if A is symmetric

Take the transpose of BTABB^T AB:

(BTAB)T=BTAT(BT)T(B^T AB)^T = B^T A^T (B^T)^T

(BTAB)T=BTATB(B^T AB)^T = B^T A^T B

For A symmetric, AT=AA^T = A:

(BTAB)T=BTAB(B^T AB)^T = B^T A B

(BTAB)T=BTAB(B^T AB)^T = B^T AB

For skew-symmetric, we need (BTAB)T=−(BTAB)(B^T AB)^T = -(B^T AB), but the result shows (BTAB)T=BTAB(B^T AB)^T = B^T AB.

Statement (A) is false.


Testing Statement (B): BTABB^T AB is symmetric if A is symmetric

Take the transpose:

(BTAB)T=BTATB(B^T AB)^T = B^T A^T B

For A symmetric, AT=AA^T = A:

(BTAB)T=BTAB(B^T AB)^T = B^T A B

(BTAB)T=BTAB(B^T AB)^T = B^T AB

This satisfies the definition of symmetric.

Statement (B) is true.


Testing Statement (C): BTABB^T AB is symmetric if A is skew-symmetric

Take the transpose:

(BTAB)T=BTATB(B^T AB)^T = B^T A^T B

For A skew-symmetric, AT=−AA^T = -A:

(BTAB)T=BT(−A)B(B^T AB)^T = B^T(-A)B

(BTAB)T=−BTAB(B^T AB)^T = -B^T AB

For symmetric, we need (BTAB)T=BTAB(B^T AB)^T = B^T AB, but the result is (BTAB)T=−BTAB(B^T AB)^T = -B^T AB.

Statement (C) is false.


Testing Statement (D): BTABB^T AB is skew-symmetric if B is skew-symmetric

This requires specific conditions on A as well and is not generally true.

Statement (D) is false.


Testing Statement (E): BTABB^T AB is symmetric if B is symmetric

For B symmetric, BT=BB^T = B:

(BTAB)T=BATB(B^T AB)^T = B A^T B

For symmetry, we need BATB=BABBA^T B = BAB, which requires AT=AA^T = A. However, A being symmetric is not given.

Statement (E) is false.


Only statement (B) is true: When A is symmetric, BTABB^T AB is always symmetric, regardless of B.

The answer is Option 3: (B) only

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