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Match List-I with List-II

List-IList-II
(Matrix)(Determinant)
(A) [17−35]\begin{bmatrix} 1 & 7 \\ -3 & 5 \end{bmatrix}(I) 24
(B) [−25−3−3]\begin{bmatrix} -2 & 5 \\ -3 & -3 \end{bmatrix}(II) 32
(C) [−128−168]\begin{bmatrix} -12 & 8 \\ -16 & 8 \end{bmatrix}(III) 21
(D) [159−21−11]\begin{bmatrix} 15 & 9 \\ -21 & -11 \end{bmatrix}(IV) 26

Choose the correct answer from the options given below:

Solution

✅ Correct Option: 2

For any 2×2 matrix [abcd]\begin{bmatrix} a & b \\ c & d \end{bmatrix}, the determinant is:

Determinant =(a×d)−(b×c)= (a × d) - (b × c)


For [17−35]\begin{bmatrix} 1 & 7 \\ -3 & 5 \end{bmatrix}:

Main diagonal: 1×5=51 × 5 = 5

Other diagonal: 7×(−3)=−217 × (-3) = -21

Determinant =5−(−21)= 5 - (-21)

=5+21= 5 + 21

=26= 26

A matches with (IV)


For [−25−3−3]\begin{bmatrix} -2 & 5 \\ -3 & -3 \end{bmatrix}:

Main diagonal: (−2)×(−3)=6(-2) × (-3) = 6

Other diagonal: 5×(−3)=−155 × (-3) = -15

Determinant =6−(−15)= 6 - (-15)

=6+15= 6 + 15

=21= 21

B matches with (III)


For [−128−168]\begin{bmatrix} -12 & 8 \\ -16 & 8 \end{bmatrix}:

Main diagonal: (−12)×8=−96(-12) × 8 = -96

Other diagonal: 8×(−16)=−1288 × (-16) = -128

Determinant =−96−(−128)= -96 - (-128)

=−96+128= -96 + 128

=32= 32

C matches with (II)


For [159−21−11]\begin{bmatrix} 15 & 9 \\ -21 & -11 \end{bmatrix}:

Main diagonal: 15×(−11)=−16515 × (-11) = -165

Other diagonal: 9×(−21)=−1899 × (-21) = -189

Determinant =−165−(−189)= -165 - (-189)

=−165+189= -165 + 189

=24= 24

D matches with (I)


Therefore, the correct matching is:

(A) - (IV), (B) - (III), (C) - (II), (D) - (I)

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