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If a>ba > b and c<0c < 0, then which of the following is NOT correct?

(A) ac<bcac < bc

(B) a+c<b+ca + c < b + c

(C) a−c<b−ca - c < b - c

(D) ac>bcac > bc

Choose the correct answer from the options given below:

Solution

✅ Correct Option: 4

Given a>ba > b and c<0c < 0.

When multiplying or dividing an inequality by a negative number, the inequality sign reverses. When adding or subtracting, the sign remains unchanged.


Statement (A): ac<bcac < bc

From a>ba > b, multiplying both sides by cc where c<0c < 0:

ac<bcac < bc

Statement (A) is correct.


Statement (B): a+c<b+ca + c < b + c

From a>ba > b, adding cc to both sides:

a+c>b+ca + c > b + c

Statement (B) is not correct.


Statement (C): a−c<b−ca - c < b - c

From a>ba > b, subtracting cc from both sides:

a−c>b−ca - c > b - c

Statement (C) is not correct.


Statement (D): ac>bcac > bc

From a>ba > b, multiplying both sides by cc where c<0c < 0:

ac<bcac < bc

Statement (D) is not correct.


Statements (B), (C), and (D) are not correct.

The answer is: (B), (C) and (D) only.

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