A shopkeeper has 300 Kg millet, a part of which he sells at 10 % profit. The remaining quantity of millet was of poor quality, and he sold it at 5 % loss. In the whole transaction, he made a profit of 7 %. The quantity of the millet sold at 5 % loss is:
A shopkeeper has 300 Kg millet, a part of which he sells at 10 % profit. The remaining quantity of millet was of poor quality, and he sold it at 5 % loss. In the whole transaction, he made a profit of 7 %. The quantity of the millet sold at 5 % loss is:
Solution
The shopkeeper has 300 Kg of millet total. One part is sold at 10% profit, and the remaining part is sold at 5% loss. Overall, he made 7% profit on the whole 300 Kg.
Let the quantity sold at 10% profit be Kg and the quantity sold at 5% loss be Kg.
Using the alligation method:
Part 1: +10% (profit)
Part 2: -5% (loss)
Overall: +7% (profit)
The ratio of quantities is found using:
Ratio = (Overall% - Part 2%) : (Part 1% - Overall%)
Total parts = 4 + 1 = 5 parts
Total millet = 300 Kg
Each part Kg
Part sold at 10% profit = 4 parts Kg
Part sold at 5% loss = 1 part Kg
Therefore, the quantity of millet sold at 5% loss is 60 Kg.
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