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The two curves x3−3xy2+15=0x^3 - 3xy^2 + 15 = 0 and 3x2y−y3+17=03x^2 y - y^3 + 17 = 0 :

Solution

✅ Correct Option: 1

From curve 1: dydx=x2−y22xy=m1\frac{dy}{dx} = \frac{x^2 - y^2}{2xy} = m_1. From curve 2: dydx=−2xyx2−y2=m2\frac{dy}{dx} = \frac{-2xy}{x^2 - y^2} = m_2. Then m1⋅m2=−1m_1 \cdot m_2 = -1, so curves cut at right angles.

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