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The rate of change of area of a circle with respect to its circumference when radius is 4cm, is

Solution

✅ Correct Option: 2

For any circle with radius rr:

Area: A=πr2A = \pi r^2

Circumference: C=2πrC = 2\pi r


To find dAdC\frac{dA}{dC}, use the chain rule:

dAdC=dA/drdC/dr\frac{dA}{dC} = \frac{dA/dr}{dC/dr}

Finding dAdr\frac{dA}{dr}:

A=πr2A = \pi r^2

dAdr=2πr\frac{dA}{dr} = 2\pi r

Finding dCdr\frac{dC}{dr}:

C=2πrC = 2\pi r

dCdr=2π\frac{dC}{dr} = 2\pi


dAdC=dA/drdC/dr\frac{dA}{dC} = \frac{dA/dr}{dC/dr}

dAdC=2πr2π\frac{dA}{dC} = \frac{2\pi r}{2\pi}

dAdC=r\frac{dA}{dC} = r


At r=4r = 4 cm:

dAdC=4\frac{dA}{dC} = 4 cm

Therefore, the rate of change of area with respect to circumference is 44 cm.

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