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A runs 3 times as fast as B. If A gives B a start of 30 meters, how far must the goal on the race course be so that A and B reach it at the same time?

Solution

✅ Correct Option: 3

Let B's speed be vv.

A runs 3 times as fast as B, so A's speed is 3v3v.

Let the goal distance from A's starting point be dd meters.


B gets a 30-meter head start, so:

  • A has to cover: dd meters
  • B has to cover: (d−30)(d - 30) meters

Since they reach the goal at the same time, their times are equal.

Time taken by A:

Time=d3v\text{Time} = \dfrac{d}{3v}

Time taken by B:

Time=d−30v\text{Time} = \dfrac{d - 30}{v}


Setting the times equal:

d3v=d−30v\dfrac{d}{3v} = \dfrac{d - 30}{v}

d3=d−30\dfrac{d}{3} = d - 30

d=3(d−30)d = 3(d - 30)

d=3d−90d = 3d - 90

d−3d=−90d - 3d = -90

−2d=−90-2d = -90

d=45d = 45


Therefore, the goal must be 45 meters from A's starting point.

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