Applied Mathematics

Financial Mathematics

Easy

applied

The present value of an immediate perpetuity of ₹ R payable at the end of every year at the rate of i per period per rupee is given by:

$R\times i$

$\frac{R}{i}$

$R+\frac{i}{2}$

$\frac{R+i}{R-i}$

✅ Correct Option: 2

Summing the infinite geometric series $\frac{R}{1+i}+\frac{R}{(1+i)^2}+\cdots$ with ratio $\frac{1}{1+i}$ gives $\frac{R}{i}$ .

2023: 11 Aug Shift 1

An asset costing Rs. 1,50,000 has a final scrap value of Rs. 25,000. If annual depreciation charge is Rs. 25,000, then useful life of the asset is :

2023: 7 June Shift 1

A vehicle has a scrap value of Rs 7,50,000 after 6 years of its purchase . If the annual depreciation charge is Rs 55,000, then the original cost of the vehicle is :

2026: 29 May Shift 2

Mr. B.M. Wadhwa purchased a car costing ₹20 lakh. It has a useful life of 15 years. The depreciation follows the straight line trend. If the annual depreciation is ₹1,20,000, what is the scrap value of the car ?

2026: 29 May Shift 2

A person invested ₹y in a mutual fund and the value of the investment at the time of redemption was ₹x. If he invested the amount for 3 years and the compound annual growth rate of his investment is 10 %, then the value of $\frac{y}{x}$ is:

2026: 14 May Shift 2

At what rate converted semi-annually will the present value of perpetuity of ₹750/- payable at the end of each 6 months be ₹ 25000?(where p.a. denotes per annum)

2023: 15 June Shift 2

A car costing ₹ 8,00,000 has scrap value of ₹ 3,00,000. If the book value of car at the end of fourth year is ₹ 6,00,000, then the useful life of the car is :

The present value of an immediate perpetuity of ₹ R payable at the end of every year at the rate of i per period per rupee is given by:

Solution

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