The solution of the initial value problem xdy/dx = 2, y(1) = 2 is Option 1: y = 2(|x| + 1) Option 2: y = 2(|x| + 2) Option 3: y = 2(2|x| + 1) Option 4: y = 2(|x| - 1)

The answer is 'y = 2(|x| + 1)'. View full solution:

CUET Mathematics - The solution of the initial value problem xdy/dx = 2, y(1) = 2 is | PYQs + Solutions

CUET Mathematics 2026 19th May Shift 1

Calculus

Easy

common

$y = 2(\log|x| + 1)$

$y = 2(\log|x| + 2)$

$y = 2(2\log|x| + 1)$

$y = 2(\log|x| - 1)$

✅ Correct Option: 1

Related questions:

13 May Shift 2

Match List-I with List-II

List-I	List-II
Differential equation	Degree
(A) $\frac{d^2y}{dx^2} + \sqrt{\frac{dy}{dx}} - y = 0$	(I) 6
(B) $\sqrt{\frac{d^3y}{dx^3}} - \sqrt[12]{\frac{d^2y}{dx^2}} = 0$	(II) Not defined
(C) $\left(\frac{d^2y}{dx^2}\right)^2 + \frac{dy}{dx} + e^{\frac{dx}{dx}} = x^2$	(III) 3
(D) $\sqrt[3]{\frac{dy}{dx}} - \frac{d^2y}{dx^2} = e^x$	(IV) 2

Choose the correct answer from the options given below:

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The solution of the differential equation $\frac{dr}{dt} = -rt, r(0) = r_0$ is

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Particular solution of the differential equation $\log\left(\frac{dy}{dx}\right) = x + y$ , given that when $x = 0, y = 0$ is: