If f(x) = cases ax^2 + b, & x < -1 \\ bx^2 + ax + 4, & x ≥ -1 cases is everywhere differentiable, then : Option 1: a = 2, b = 3 Option 2: a = 3, b = 2 Option 3: a = -2, b = 3 Option 4: a = 2, b = -3

The answer is 'a = 2, b = 3'. View full solution:

CUET Mathematics - If f(x) = cases ax^2 + b, & x < -1 \\ bx^2 + ax + 4, & x ≥ -1 cases is everywhere differentiable, then : | PYQs + Solutions

CUET Mathematics 2023 22 May Shift 3

Calculus

Medium

$a = 2, b = 3$

$a = 3, b = 2$

$a = -2, b = 3$

$a = 2, b = -3$

✅ Correct Option: 1

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