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The value of C, in Rolle's theorem for the function f(x)=exsin⁡xf(x) = e^x \sin x, when x∈[0,π]x \in [0, \pi] is :

Solution

✅ Correct Option: 4

f(0)=0f(0)=0, f(π)=0f(\pi)=0, ff continuous and differentiable, so Rolle's applies.

f′(x)=ex(sin⁡x+cos⁡x)=0⇒tan⁡x=−1f'(x)=e^x(\sin x+\cos x)=0 \Rightarrow \tan x=-1.

In [0,π][0,\pi]: x=3π4x=\frac{3\pi}{4}.

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