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The equation of the normal to the curve y=x−1xy = x - \frac{1}{x} at (1,0)(1,0) is:

Solution

✅ Correct Option: 3

dydx=1+1x2\frac{dy}{dx} = 1 + \frac{1}{x^2}. At x=1x=1, slope of tangent is 2, so slope of normal is −12-\frac{1}{2}. Equation: y−0=−12(x−1)y - 0 = -\frac{1}{2}(x-1), giving x+2y=1x + 2y = 1.

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