CUET Mathematics 2023 22 May Shift 3 PYQs

The probability of not getting 53 Sundays in a leap year is

Let E and F be two events such that $P(E) = \frac{1}{3}$, $P(F) = \frac{1}{4}$ and $P(E \cap F) = \frac{1}{5}$. Then the value of $P(F|E)$ is equal to

How many minimum number of times must a man toss a fair coin so that the probability of having at least one head is more than 90%?