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The equation of tangent to the curve x=acos⁡3t,y=asin⁡3tx = a \cos^3 t, y = a \sin^3 t at t is :

Solution

✅ Correct Option: 1

dydx=3asin⁡2tcos⁡t−3acos⁡2tsin⁡t=−tan⁡t\frac{dy}{dx}=\frac{3a\sin^2 t\cos t}{-3a\cos^2 t\sin t}=-\tan t.

Tangent at (acos⁡3t,asin⁡3t)(a\cos^3 t, a\sin^3 t): y−asin⁡3t=−tan⁡t(x−acos⁡3t)y-a\sin^3 t=-\tan t(x-a\cos^3 t).

Simplifying: xsin⁡t+ycos⁡t=asin⁡tcos⁡tx\sin t+y\cos t=a\sin t\cos t. Dividing by sin⁡tcos⁡t\sin t\cos t gives xsec⁡t+ycsc⁡t=ax\sec t+y\csc t=a.

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