If A = pmatrix 2 & 2 \\ - 2 & 2 pmatrix, then A^2 = Option 1: pmatrix 4 & 4 \\ - 4 & 4 pmatrix Option 2: pmatrix ^2 2 & ^2 2 \\ ^2 2 & ^2 2 pmatrix Option 3: pmatrix 1 & 0 \\ 2 & 2 pmatrix Option 4: pmatrix 6 & 6 \\ - 6 & 6 pmatrix

The answer is 'pmatrix 4 & 4 \\ - 4 & 4 pmatrix'. View full solution:

If A = ±atrix 2 & 2 \\ - 2 & 2 ±atrix, then A^2 =

±atrix 4 & 4 \\ - 4 & 4 ±atrix

±atrix ^2 2 & ^2 2 \\ ^2 2 & ^2 2 ±atrix

±atrix 6 & 6 \\ - 6 & 6 ±atrix

CUET Mathematics 2023 22 May Shift 3

Algebra

Medium

$\begin{pmatrix} \cos 4\theta & \sin 4\theta \\ -\sin 4\theta & \cos 4\theta \end{pmatrix}$

$\begin{pmatrix} \cos^2 2\theta & \sin^2 2\theta \\ \sin^2 2\theta & \cos^2 2\theta \end{pmatrix}$

$\begin{pmatrix} 1 & 0 \\ \sin 2\theta & \cos 2\theta \end{pmatrix}$

$\begin{pmatrix} \cos 6\theta & \sin 6\theta \\ -\sin 6\theta & \cos 6\theta \end{pmatrix}$

✅ Correct Option: 1