Match **List - I** with **List - II**. | | List - I (Matrix) | | List - II (Type) | |---|---|---|---| | (A) | bmatrix 5 & 0 & 0 \ 0 & 5 & 0 \ 0 & 0 & 5 bmatrix | (I) | Lower Triangular Matrix | | (B) | bmatrix 1 & 5 & 0 & -1 bmatrix | (II) | Row Matrix | | (C) | bmatrix 3 & 0 & 0 \ 1 & -1 & 0 \ 2 & 5 & 4 bmatrix | (III) | Diagonal Matrix | | (D) | bmatrix 1 & 0 & 0 \ 0 & 2 & 0 \ 0 & 0 & 4 bmatrix | (IV) | Scalar Matrix | Choose the **correct** answer from the options given below :

Question

Option 1: (A)-(I), (B)-(II), (C)-(III), (D)-(IV)

Option 2: (A)-(II), (B)-(III), (C)-(IV), (D)-(I)

Option 3: (A)-(IV), (B)-(II), (C)-(I), (D)-(III)

Option 4: (A)-(III), (B)-(IV), (C)-(II), (D)-(I)

AfterBoards · Accepted Answer

The answer is '(A)-(IV), (B)-(II), (C)-(I), (D)-(III)'. View full solution:

CUET Mathematics 2023 22 May Shift 3 PYQs

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