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For testing the difference between the means of two samples, the following data is available :

SizeMeanVariance
Sample 1540101
Sample 273060

The value of the t-statistics is :

Solution

✅ Correct Option: 1

Pooled variance Sp2=n1s12+n2s22n1+n2−2=505+42010=92.5=1852S_p^2=\frac{n_1 s_1^2+n_2 s_2^2}{n_1+n_2-2}=\frac{505+420}{10}=92.5=\frac{185}{2}.

t=x1ˉ−x2ˉSp2(1/n1+1/n2)=1092.5⋅12/35=10222/7=107222t=\frac{\bar{x_1}-\bar{x_2}}{\sqrt{S_p^2(1/n_1+1/n_2)}}=\frac{10}{\sqrt{92.5\cdot 12/35}}=\frac{10}{\sqrt{222/7}}=10\sqrt{\frac{7}{222}}.

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