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The value of the determinant Δ=∣1!2!3!2!3!4!3!4!5!∣\Delta = \begin{vmatrix} 1! & 2! & 3! \\ 2! & 3! & 4! \\ 3! & 4! & 5! \end{vmatrix} is :

Solution

✅ Correct Option: 3

Substituting factorial values: ∣1262624624120∣\begin{vmatrix}1 & 2 & 6\\ 2 & 6 & 24\\ 6 & 24 & 120\end{vmatrix}.

Expanding: 1(720−576)−2(240−144)+6(48−36)=144−192+72=24=4!1(720-576)-2(240-144)+6(48-36)=144-192+72=24=4!.

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