Skip to main contentSkip to solution

The function f(x)=x3+2x2−1f(x) = x^3 + 2x^2 - 1 is

(A) increasing in (−43,0)\left(\dfrac{-4}{3}, 0\right)

(B) decreasing in (−43,0)\left(\dfrac{-4}{3}, 0\right)

(C) increasing in (−∞,−43)\left(-\infty, \dfrac{-4}{3}\right)

(D) increasing in (0,∞)(0, \infty)

Choose the correct answer from the options given below:

Solution

✅ Correct Option: 3

f′(x)=3x2+4x=x(3x+4)f'(x)=3x^2+4x=x(3x+4), which vanishes at x=−43x=-\dfrac43 and x=0x=0. The product is positive on (−∞,−43)\left(-\infty,-\dfrac43\right) and on (0,∞)(0,\infty), and negative on (−43,0)\left(-\dfrac43,0\right). So (B), (C), (D) are correct.

Keyboard Shortcuts

  • Left arrow: Previous question
  • Right arrow: Next question
  • S key: Jump to solution
  • Q key: Jump to question