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The area enclosed between the curve x2+y2=16x^2 + y^2 = 16 and the coordinate axes in the first quadrant is :

Solution

✅ Correct Option: 3

Circle x2+y2=16x^2+y^2=16 has radius 4. Total area =πr2=16π=\pi r^2=16\pi.

Area in first quadrant =16π4=4π=\frac{16\pi}{4}=4\pi sq. units.

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