Match **List - I** with **List - II**. | | List - I | | List - II | |---|---|---|---| | (A) | f(x) = 1/x, f : R - \0\ R - \0\ | (I) | neither injective nor surjective | | (B) | f(x) = x^2, f : N N | (II) | surjective but not injective | | (C) | f(x) = x^2, f : R R | (III) | injective but not surjective | | (D) | f : \1, 2, 3\ \1, 2\ defined as f : \(1, 1), (2, 2), (3, 1)\ | (IV) | injective and surjective | Choose the **correct** answer from the options given below :

Question

Option 1: (A)-(IV), (B)-(I), (C)-(II), (D)-(III)

Option 2: (A)-(III), (B)-(IV), (C)-(I), (D)-(II)

Option 3: (A)-(II), (B)-(III), (C)-(IV), (D)-(I)

Option 4: (A)-(IV), (B)-(III), (C)-(I), (D)-(II)

AfterBoards · Accepted Answer

The answer is '(A)-(IV), (B)-(III), (C)-(I), (D)-(II)'. View full solution:

CUET Mathematics 2023 22 May Shift 3 PYQs

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