Skip to main contentSkip to solution

If x2/3+y2/3=a2/3x^{2/3} + y^{2/3} = a^{2/3}, then dydx\frac{dy}{dx} is equal to :

Solution

✅ Correct Option: 1

Differentiating x2/3+y2/3=a2/3x^{2/3}+y^{2/3}=a^{2/3} implicitly:

23x−1/3+23y−1/3dydx=0\frac{2}{3}x^{-1/3}+\frac{2}{3}y^{-1/3}\frac{dy}{dx}=0.

dydx=−x−1/3y−1/3=−(yx)1/3=−yx3\frac{dy}{dx}=-\frac{x^{-1/3}}{y^{-1/3}}=-\left(\frac{y}{x}\right)^{1/3}=-\sqrt[3]{\frac{y}{x}}.

Keyboard Shortcuts

  • Left arrow: Previous question
  • Right arrow: Next question
  • S key: Jump to solution
  • Q key: Jump to question