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If f(x)={x2−9x−3,x≠35,x=3f(x) = \begin{cases} \frac{x^2 - 9}{x - 3}, & x \neq 3 \\ 5, & x = 3 \end{cases} then f(x)f(x) :

Solution

✅ Correct Option: 2

lim⁡x→3x2−9x−3=lim⁡x→3(x+3)=6\lim_{x \to 3} \frac{x^2-9}{x-3} = \lim_{x \to 3}(x+3) = 6.

f(3)=5≠6f(3) = 5 \neq 6.

Limit exists but ≠f(3)\neq f(3), so discontinuity is removable.

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