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Let a⃗=4i^−j^+3k^\vec{a} = 4\hat{i} - \hat{j} + 3\hat{k} and b⃗=−2i^+j^−2k^\vec{b} = -2\hat{i} + \hat{j} - 2\hat{k}. Then

(A) a⃗\vec{a} is a unit vector

(B) a⃗×b⃗=−i^+2j^+2k^\vec{a} \times \vec{b} = -\hat{i} + 2\hat{j} + 2\hat{k}

(C) a⃗\vec{a} and b⃗\vec{b} are parallel vectors

(D) a⃗\vec{a} and b⃗\vec{b} are neither parallel nor perpendicular vectors

Choose the correct answer from the options given below :

Solution

✅ Correct Option: 4

∣a⃗∣=26|\vec{a}| = \sqrt{26}, not unit (A false).

a⃗×b⃗=−i^+2j^+2k^\vec{a} \times \vec{b} = -\hat{i} + 2\hat{j} + 2\hat{k} (B true).

a⃗⋅b⃗=−8−1−6=−15≠0\vec{a} \cdot \vec{b} = -8-1-6 = -15 \neq 0, not perpendicular.

a⃗×b⃗≠0\vec{a} \times \vec{b} \neq 0, not parallel (D true).

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