If bmatrix 3 & 2x+5y & -2 \\ x+4y & 7 & -5 bmatrix = bmatrix 3 & 10 & -2 \\ 2 & 7 & -5 bmatrix Then the values of x and y are : Option 1: x = -2, y = 6 Option 2: x = 12, y = 5 Option 3: x = -4, y = 7 Option 4: x = 10, y = -2

The answer is 'x = 10, y = -2'. View full solution:

CUET Mathematics - If bmatrix 3 & 2x+5y & -2 \\ x+4y & 7 & -5 bmatrix = bmatrix 3 & 10 & -2 \\ 2 & 7 & -5 bmatrix Then the values of x and y are : | PYQs + Solutions

CUET Mathematics 2023 15 June Shift 2

Algebra

Easy

$x = -2$ , $y = 6$

$x = 12$ , $y = 5$

$x = -4$ , $y = 7$

$x = 10$ , $y = -2$

✅ Correct Option: 4

Related questions:

22 May Shift 2

If $\begin{bmatrix} ab & cd \\ a+c & b+d \end{bmatrix} = \begin{bmatrix} 2 & -3 \\ 4 & 1 \end{bmatrix}$ where $a$ , $b$ , $c$ , $d$ are integers, then which of the following are true?

(A) $a + d = 0$

(B) $b + d = 3$

(D) $c + d = 2$

Choose the correct answer from the options given below:

26 May Shift 2

Match List-I with List-II

List-I	List-II
Matrix/equations	Values
(A) $\begin{bmatrix} 2x+1 & 3y \\ 0 & y^2-5y \end{bmatrix} = \begin{bmatrix} x+3 & y^2+2 \\ 0 & -6 \end{bmatrix}$	(I) $x = 2, y = -1$
(B) $\begin{bmatrix} 1 & 2 & -1 \\ x & 0 & 3 \\ y & 3 & 4 \end{bmatrix}$ is symmetric	(II) $x = 2, y = 2$
(C) $[x \ \ 1]\begin{bmatrix} 1 & 0 \\ -2 & -3 \end{bmatrix}\begin{bmatrix} 5 & 2 \\ 0 & y \end{bmatrix} = O$	(III) $x = -2, y = 2$
(D) $\begin{bmatrix} x & 0 \\ 1 & 1 \end{bmatrix}\begin{bmatrix} x & 0 \\ 1 & 1 \end{bmatrix} = \begin{bmatrix} 4 & 0 \\ -1 & y/2 \end{bmatrix}$	(IV) $x = 2, y = 0$

Choose the correct answer from the options given below:

30 Aug Shift 1

Assume $P$ , $Q$ , $R$ and $S$ are matrices of order $2 \times m$ , $k \times n$ , $m \times 2$ and $2 \times 3$ respectively. The restrictions on $k$ , $m$ and $n$ , so that $PQ + RS$ is defined are

CUET Mathematics 2023 15 June Shift 2 PYQs

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