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If [32x+5y−2x+4y7−5]=[310−227−5]\begin{bmatrix} 3 & 2x+5y & -2 \\ x+4y & 7 & -5 \end{bmatrix} = \begin{bmatrix} 3 & 10 & -2 \\ 2 & 7 & -5 \end{bmatrix} Then the values of xx and yy are :

Solution

✅ Correct Option: 4

2x+5y=102x + 5y = 10 and x+4y=2x + 4y = 2.

From second: x=2−4yx = 2 - 4y. Substitute: 2(2−4y)+5y=10⇒−3y=6⇒y=−22(2-4y) + 5y = 10 \Rightarrow -3y = 6 \Rightarrow y = -2.

x=2−4(−2)=10x = 2 - 4(-2) = 10.

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