The shortest distance between the lines x+3/1 = y-2/2 = z+4/3 and x+3/-3 = y+7/2 = z-6/4 is : Option 1: 197sqrt(179) Option 2: 197sqrt(191) Option 3: 197sqrt(189) Option 4: 197sqrt(237)

The answer is '197sqrt(237)'. View full solution:

CUET Mathematics - The shortest distance between the lines x+3/1 = y-2/2 = z+4/3 and x+3/-3 = y+7/2 = z-6/4 is : | PYQs + Solutions

CUET Mathematics 2023 15 June Shift 2

Geometry

Hard

$\frac{197}{\sqrt{179}}$

$\frac{197}{\sqrt{191}}$

$\frac{197}{\sqrt{189}}$

$\frac{197}{\sqrt{237}}$

✅ Correct Option: 4

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CUET Mathematics 2023 15 June Shift 2 PYQs

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