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The value of 2y−3x2y - 3x, if 2[x57y−3]+[3−412]=[761514]2\begin{bmatrix} x & 5 \\ 7 & y-3 \end{bmatrix} + \begin{bmatrix} 3 & -4 \\ 1 & 2 \end{bmatrix} = \begin{bmatrix} 7 & 6 \\ 15 & 14 \end{bmatrix} is :

Solution

✅ Correct Option: 1

Equating elements: 2x+3=7⇒x=22x + 3 = 7 \Rightarrow x = 2.

2(y−3)+2=14⇒2y=18⇒y=92(y-3) + 2 = 14 \Rightarrow 2y = 18 \Rightarrow y = 9.

2y−3x=18−6=122y - 3x = 18 - 6 = 12.

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