The points of discontinuity of the function f defined by f(x) = cases x+2 & x ≤ 1 \\ x-2 & 1 < x < 2 \\ 0 & x ≥ 2 cases are : Option 1: 0 and 1 Option 2: 1 and 2 Option 3: 1 Option 4: 2

The answer is '1'. View full solution:

CUET Mathematics - The points of discontinuity of the function f defined by f(x) = cases x+2 & x ≤ 1 \\ x-2 & 1 < x < 2 \\ 0 & x ≥ 2 cases are : | PYQs + Solutions

CUET Mathematics 2023 15 June Shift 2

Calculus

Easy

0 and 1

1 and 2

✅ Correct Option: 3

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Match List-I with List-II

$\begin{array}{|l|l|} \hline \rule{0pt}{2.8ex}\text{List-I} & \text{List-II} \\[1.2ex] \hline \rule{0pt}{2.8ex}\text{(A) } f(x) = |x| & \text{(I) Not differentiable at } x=-2 \text{ only} \\[1.2ex] \hline \rule{0pt}{2.8ex}\text{(B) } f(x) = |x+2| & \text{(II) Not differentiable at } x=0 \text{ only} \\[1.2ex] \hline \rule{0pt}{2.8ex}\text{(C) } f(x) = |x^2-4| & \text{(III) Not differentiable at } x=2 \text{ only} \\[1.2ex] \hline \rule{0pt}{2.8ex}\text{(D) } f(x) = |x-2| & \text{(IV) Not differentiable at } x=2,-2 \text{ only} \\[1.2ex] \hline \end{array}$

Choose the correct answer from the options given below:

CUET Mathematics 2023 15 June Shift 2 PYQs

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