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The minimum value of z=3x+6yz = 3x + 6y subject to the constraints 2x+3y≤1802x + 3y \leq 180, x+y≥60x + y \geq 60, x≥3yx \geq 3y, x≥0x \geq 0, y≥0y \geq 0 is :

Solution

✅ Correct Option: 2

Vertices of feasible region: (45,15),(60,20),(90,0),(60,0)(45,15), (60,20), (90,0), (60,0).

Values of z=3x+6yz = 3x + 6y: 225,300,270,180225, 300, 270, 180.

Minimum =180= 180.

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