Applied Mathematics

Time Based Data

Easy

applied

If Paasche's index number is 160 and Laspeyre's index number is 250, then Fisher's index number is :

150

200

300

✅ Correct Option: 2

Fisher's index $= \sqrt{\text{Laspeyre's} \times \text{Paasche's}}$ .

$= \sqrt{250 \times 160} = \sqrt{40000} = 200$ .

2026: 21 May Shift 2

For the given five values, 13, 17, 21, 25, 35, the three years moving averages are:

2026: 14 May Shift 2

The 3-year moving averages for the loan (in lakh ₹) issued by a finance company for startups in different cities of India based on the values given below will be:

Year	2019	2020	2021	2022	2023	2024
Loan amount	25	20	18	13	23	12

2023: 30 May Shift 3

Using simple average of relatives method, the price index for 2011, taking 2001 as base year, was found to be 127. If $\Sigma p_0 = 263$ , then x and y from the following data are :

Commodities	A	B	C	D	E	F
Prices (in Rs.) in 2001	80	70	x	20	18	25
Prices (in Rs.) in 2011	100	87.50	61	22	y	32.50

2023: 23 May Shift 3

The rise in prices before Christmas is an example of

2023: 7 June Shift 1

For a given data of 5 observation $\sum y = 311$ , $\sum x^2 = 10$ and $\sum xy = 90$ . The equation of the trend line is :

2023: 15 June Shift 2

In the equation of trend line $y_t = a + bx$ , a and b represent :

If Paasche's index number is 160 and Laspeyre's index number is 250, then Fisher's index number is :

Solution

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