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Consider the following hypothesis test :

H0:μ≤20H_0 : \mu \leq 20

H1:μ>20H_1 : \mu > 20

A sample of 81 produced a sample mean of 20.55. The population standard deviation is 3. The value of the test statistic is :

Solution

✅ Correct Option: 4

z=xˉ−μσ/n=20.55−203/81=0.551/3=1.65z = \frac{\bar{x} - \mu}{\sigma/\sqrt{n}} = \frac{20.55 - 20}{3/\sqrt{81}} = \frac{0.55}{1/3} = 1.65.

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