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The total cost function for xx units of a commodity is given by C(x)=25x33−75x2+48x+34C(x) = \frac{25x^3}{3} - 75x^2 + 48x + 34. The output xx at which the marginal cost is minimum is :

Solution

✅ Correct Option: 2

Marginal Cost =C′(x)=25x2−150x+48= C'(x) = 25x^2 - 150x + 48.

For minimum: d(MC)dx=50x−150=0\frac{d(MC)}{dx} = 50x - 150 = 0.

x=3x = 3.

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