CUET Mathematics 2023 15 June Shift 2 PYQs

The slope of the normal to the curve $y = 2x^2$ at $x = 1$ is:

The equation of the normal to the curve $y = x - \frac{1}{x}$ at $(1,0)$ is:

The maximum value of $f(x) = \frac{1}{4x^2 + 2x + 1}$ is