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The random variable X has a probability distribution P(X) of the following form, where k is some number.

P(X=x)={k,if x=02k,if x=13k,if x=20,otherwiseP(X=x) = \begin{cases} k, & \text{if } x=0 \\ 2k, & \text{if } x=1 \\ 3k, & \text{if } x=2 \\ 0, & \text{otherwise} \end{cases}

Then P(x≤2)P(x \leq 2) is :

Solution

✅ Correct Option: 2

Sum of probabilities: k+2k+3k=6k=1⇒k=16k + 2k + 3k = 6k = 1 \Rightarrow k = \frac{1}{6}.

P(X≤2)=P(0)+P(1)+P(2)=6k=1P(X \leq 2) = P(0) + P(1) + P(2) = 6k = 1.

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