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The rate of change of the area of a circular disc with respect to its circumference when radius is 3 is :

Solution

✅ Correct Option: 2

A=πr2A = \pi r^2, C=2πrC = 2\pi r.

dAdC=dA/drdC/dr=2πr2π=r\frac{dA}{dC} = \frac{dA/dr}{dC/dr} = \frac{2\pi r}{2\pi} = r.

At r=3r = 3: dAdC=3\frac{dA}{dC} = 3.

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