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If y=500e7x+600e−7xy = 500 e^{7x} + 600 e^{-7x} and d2ydx2=ky\frac{d^2 y}{dx^2} = ky, then the value of k is :

Solution

✅ Correct Option: 3

Differentiating twice:

dydx=3500e7x−4200e−7x\frac{dy}{dx} = 3500 e^{7x} - 4200 e^{-7x}.

d2ydx2=24500e7x+29400e−7x=49(500e7x+600e−7x)=49y\frac{d^2 y}{dx^2} = 24500 e^{7x} + 29400 e^{-7x} = 49(500 e^{7x} + 600 e^{-7x}) = 49 y.

So k=49k = 49.

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