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Match List-I with List-II

List-IList-II
(A) y+dydx=14∫y dxy + \frac{dy}{dx} = \frac{1}{4}\int y\,dx(I) Order 1, Degree 1
(B) y=dydx+Cdy/dxy = \frac{dy}{dx} + \frac{C}{dy/dx}(II) Order 2, Degree 2
(C) (xy2+x)dx+(y−x2)dy=0(xy^2+x)dx + (y-x^2)dy = 0(III) Order 2, Degree 1
(D) [{1+(dydx)2}3/2/d2ydx2]=K\left[\left\{1+\left(\frac{dy}{dx}\right)^2\right\}^{3/2}/\frac{d^2y}{dx^2}\right] = K(IV) Order 1, Degree 2

Choose the correct answer from the options given below:

Solution

✅ Correct Option: 2

(A) differentiate to remove the integral: order 2, degree 1 →\to III. (B) multiply by dy/dxdy/dx: order 1, degree 2 →\to IV. (C) is order 1, degree 1 →\to I. (D) squaring after cross-multiplying gives order 2, degree 2 →\to II.

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