Skip to main contentSkip to solution

The matrix X such that it satisfies the equation: X[321−1]=[4123]X\begin{bmatrix} 3 & 2 \\ 1 & -1 \end{bmatrix} = \begin{bmatrix} 4 & 1 \\ 2 & 3 \end{bmatrix} is

Solution

✅ Correct Option: 4

Post-multiply by the inverse: X=[4123]A−1X = \begin{bmatrix} 4 & 1 \\ 2 & 3 \end{bmatrix}A^{-1} where A=[321−1]A = \begin{bmatrix} 3 & 2 \\ 1 & -1 \end{bmatrix} and ∣A∣=−5|A| = -5. Computing gives X=[111−1]X = \begin{bmatrix} 1 & 1 \\ 1 & -1 \end{bmatrix}, which can be verified by direct multiplication.

Keyboard Shortcuts

  • Left arrow: Previous question
  • Right arrow: Next question
  • S key: Jump to solution
  • Q key: Jump to question