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For a certain data (xi,yi)(x_i, y_i), i=1,2,...,7i = 1,2,...,7: ∑i=17yi=246\sum_{i=1}^{7} y_i = 246 and ∑i=17uiyi=29\sum_{i=1}^{7} u_iy_i = 29, ∑i=17ui2=28\sum_{i=1}^{7} u_i^2 = 28 where ui=xi−2004u_i = x_i - 2004, then straight line trend by the method of least square is :

Solution

✅ Correct Option: 2

With u=x−2004u = x - 2004 and ∑u=0\sum u = 0, the estimates are a=∑yn=2467=35.14a = \frac{\sum y}{n} = \frac{246}{7} = 35.14 and b=∑uy∑u2=2928=1.036b = \frac{\sum uy}{\sum u^2} = \frac{29}{28} = 1.036. So the trend line is y=35.14+1.036(x−2004)y = 35.14 + 1.036(x-2004).

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