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If the sum of the lengths of hypotenuse and a side of a right angled triangle is given, then the area of the triangle is maximum when angle between them is:

Solution

✅ Correct Option: 4

Let hypotenuse hh, side xx, with h+x=kh + x = k and included angle θ\theta. Area =12xh2−x2= \frac{1}{2}x\sqrt{h^2-x^2}. Maximising gives h=2xh = 2x, so cos⁡θ=x/h=1/2\cos\theta = x/h = 1/2 and θ=π/3\theta = \pi/3.

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