Skip to main contentSkip to solution

A die is thrown twice and the sum of the numbers appearing is observed to be 6. Then the probability that the number 4 has appeared at least once, is

Solution

✅ Correct Option: 4

Sum 6 occurs in 5 ways: (1,5),(2,4),(3,3),(4,2),(5,1)(1,5),(2,4),(3,3),(4,2),(5,1). Of these, 4 appears in (2,4)(2,4) and (4,2)(4,2), i.e. 2 cases. So the conditional probability is 2/52/5.

Keyboard Shortcuts

  • Left arrow: Previous question
  • Right arrow: Next question
  • S key: Jump to solution
  • Q key: Jump to question