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The general solution of the differential equation dydx+ycot⁡x=2cos⁡x\frac{dy}{dx} + y\cot x = 2\cos x is (Where C is an arbitrary constant)

Solution

✅ Correct Option: 3

IF =e∫cot⁡x dx=sin⁡x= e^{\int\cot x\,dx} = \sin x. Then ddx(ysin⁡x)=2sin⁡xcos⁡x=sin⁡2x\frac{d}{dx}(y\sin x) = 2\sin x\cos x = \sin 2x, so ysin⁡x=sin⁡2x+Cy\sin x = \sin^2 x + C. Rearranging, (y−sin⁡x)sin⁡x=C(y - \sin x)\sin x = C.

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