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The monthly expectation of a two-wheeler accident at a particular railway crossing is 0.02. What is the probability that in a specific month, no accident occurred? (given e−0.02=0.9802e^{-0.02} = 0.9802)

Solution

✅ Correct Option: 3

With a Poisson model of mean λ=0.02\lambda = 0.02, P(X=0)=e−λλ0/0!=e−0.02=0.9802P(X=0) = e^{-\lambda}\lambda^0/0! = e^{-0.02} = 0.9802.

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