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The area of the region bounded by the line 3y=−2x+73y = -2x + 7, x-axis and the lines x=0x = 0 and x=4x = 4, is (in Sq. units)

Solution

✅ Correct Option: 3

The line y=(7−2x)/3y = (7-2x)/3 crosses the x-axis at x=3.5x = 3.5, so the region lies above the axis on [0,3.5][0, 3.5] and below on [3.5,4][3.5, 4]. Areas are 49/1249/12 and 1/121/12, summing to 50/12=25/650/12 = 25/6 sq. units.

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