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A container contains 100 litres of acid. From the container, 10 litres acid was taken out and replaced by equal amount of water. This process was repeated further twice, then the amount of acid left in the container is:

Solution

✅ Correct Option: 2

Each replacement leaves a fraction (1−10100)\left(1 - \frac{10}{100}\right) of the acid. After three operations the acid is 100(0.9)3=100(0.729)=72.9100(0.9)^3 = 100(0.729) = 72.9 litres.

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