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The sum of order and degree of differential equation 2x2⋅(d2ydx2)−3⋅(dydx)3+y=02x^2 \cdot \left(\frac{d^2y}{dx^2}\right) - 3 \cdot \left(\frac{dy}{dx}\right)^3 + y = 0 is

Solution

✅ Correct Option: 2

The highest order derivative present is d2ydx2\frac{d^2y}{dx^2}, so order =2= 2.

The power of the highest order derivative is 1, so degree =1= 1.

Sum of order and degree =2+1=3= 2 + 1 = 3.

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