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Two cards are drawn successively with replacement from a well shuffled pack of 52 playing cards. Which of the following is correct probability distribution of number of Queens(X) as (XP(X))\binom{X}{P(X)}?

Solution

✅ Correct Option: 1

With replacement, each draw gives a queen with probability 452=113\frac{4}{52} = \frac{1}{13}, so X is binomial with n=2n=2. Then P(0)=144169P(0) = \frac{144}{169}, P(1)=2⋅113⋅1213=24169P(1) = 2\cdot\frac{1}{13}\cdot\frac{12}{13} = \frac{24}{169} and P(2)=1169P(2) = \frac{1}{169}.

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